The formula for a quadratic equation is used to find the roots of the equation. Since quadratics have a degree equal to two, therefore there will be two solutions for the equation. Suppose ax² + bx + c = 0 is the quadratic equation, then the formula to find the roots of this equation will be:
x = [-b±√(b2-4ac)]/2a
The sign of plus/minus indicates there will be two solutions for x. Learn in detail the quadratic formula here.
Examples of Quadratics
Beneath are the illustrations of quadratic equations of the form (ax² + bx + c = 0)
- x² –x – 9 = 0
- 5x² – 2x – 6 = 0
- 3x² + 4x + 8 = 0
- -x² +6x + 12 = 0
Examples of a quadratic equation with the absence of a ‘ C ‘- a constant term.
- -x² – 9x = 0
- x² + 2x = 0
- -6x² – 3x = 0
- -5x² + x = 0
- -12x² + 13x = 0
- 11x² – 27x = 0
Following are the examples of a quadratic equation in factored form
- (x – 6)(x + 1) = 0 [ result obtained after solving is x² – 5x – 6 = 0]
- –3(x – 4)(2x + 3) = 0 [result obtained after solving is -6x² + 15x + 36 = 0]
- (x − 5)(x + 3) = 0 [result obtained after solving is x² − 2x − 15 = 0]
- (x – 5)(x + 2) = 0 [ result obtained after solving is x² – 3x – 10 = 0]
- (x – 4)(x + 2) = 0 [result obtained after solving is x² – 2x – 8 = 0]
- (2x+3)(3x – 2) = 0 [result obtained after solving is 6x² + 5x – 6]
Below are the examples of a quadratic equation with an absence of linear co – efficient ‘ bx’
- 2x² – 64 = 0
- x² – 16 = 0
- 9x² + 49 = 0
- -2x² – 4 = 0
- 4x² + 81 = 0
- -x² – 9 = 0
RELATED POSTS
View all
