There are basically four methods of solving quadratic equations. They are:
- Factoring
- Completing the square
- Using Quadratic Formula
- Taking the square root
Factoring of Quadratics
- Begin with a equation of the form ax² + bx + c = 0
- Ensure that it is set to adequate zero.
- Factor the left-hand side of the equation by assuming zero on the right-hand side of the equation.
- Assign each factor equal to zero.
- Now solve the equation in order to determine the values of x.
Suppose if the main coefficient is not equal to one then deliberately, you have to follow a methodology in the arrangement of the factors.
Example:
2x²-x-6=0
(2x+3)(x-2)=0
2x+3=0
x=-3/2
x=2
Completing the Square Method
Let us learn this method with example.
Example: Solve 2x2 – x – 1 = 0.
First, move the constant term to the other side of the equation.
2x2 – x = 1
Dividing both sides by 2.
x2 – x/2 = ½
Add the square of half of the coefficient of x, (b/2a)2, on both the sides, i.e., 1/16
x2 – x/2 + 1/16 = ½ + 1/16
Now we can factor the right side,
(x-¼)2 = 9/16 = (¾)2
Taking root on both sides;
X – ¼ = ±3/4
Add ¼ on both sides
X = ¼ ± ¾
Therefore,
X = ¼ + ¾ = 4/4 = 1
X = ¼ – ¾ = -2/4 = -½
Using Quadratic Formula
For the given Quadratic equation of the form, ax² + bx + c = 0
Therefore the roots of the given equation can be found by:
where ± (one plus and one minus) represent two distinct roots of the given equation.
Taking the Square Root
We can use this method for the equations such as:
x2 + a2 = 0
Example: Solve x2 – 50 = 0.
x2 – 50 = 0
x2 = 50
Taking the roots both sides
√x2 = ±√50
x = ±√(2 x 5 x 5)
x = ±5√2
Thus, we got the required solution.
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