Learning Objectives
In this section, you will:
- Identify the degree and leading coefficient of polynomials.
- Add and subtract polynomials.
- Multiply polynomials.
- Use FOIL to multiply binomials.
- Perform operations with polynomials of several variables.
Maahi is building a little free library (a small house-shaped book repository), whose front is in the shape of a square topped with a triangle. There will be a rectangular door through which people can take and donate books. Maahi wants to find the area of the front of the library so that they can purchase the correct amount of paint. Using the measurements of the front of the house, shown inΒ Figure 1, we can create an expression that combines several variable terms, allowing us to solve this problem and others like it.
Figure 1
First find the area of the square in square feet.
A===s2(2x)24×2π΄=π 2=(2π₯)2=4π₯2
Then find the area of the triangle in square feet.
A===12bh12(2x)(32)32xπ΄=12πβ=12(2π₯)(32)=32π₯
Next find the area of the rectangular door in square feet.
A===lwxβ 1xπ΄=ππ€=π₯β 1=π₯
The area of the front of the library can be found by adding the areas of the square and the triangle, and then subtracting the area of the rectangle. When we do this, we get 4×2+32xβxft2,4π₯2+32π₯βπ₯ft2, or 4×2+12×4π₯2+12π₯ ft2.
In this section, we will examine expressions such as this one, which combine several variable terms.
Identifying the Degree and Leading Coefficient of Polynomials
The formula just found is an example of a polynomial, which is a sum of or difference of terms, each consisting of a variable raised to a nonnegative integer power. A number multiplied by a variable raised to an exponent, such as 384Ο,384π, is known as a coefficient. Coefficients can be positive, negative, or zero, and can be whole numbers, decimals, or fractions. Each product aixi,πππ₯π, such as 384Οw,384ππ€, is a term of a polynomial. If a term does not contain a variable, it is called a constant.
A polynomial containing only one term, such as 5×4,5π₯4, is called a monomial. A polynomial containing two terms, such as 2xβ9,2π₯β9, is called a binomial. A polynomial containing three terms, such as β3×2+8xβ7,β3π₯2+8π₯β7, is called a trinomial.
We can find the degree of a polynomial by identifying the highest power of the variable that occurs in the polynomial. The term with the highest degree is called the leading term because it is usually written first. The coefficient of the leading term is called the leading coefficient. When a polynomial is written so that the powers are descending, we say that it is in standard form.
POLYNOMIALS
A polynomial is an expression that can be written in the form
anxn+…+a2x2+a1x+a0πππ₯π+…+π2π₯2+π1π₯+π0
Each real number ai is called a coefficient. The number a0π0 that is not multiplied by a variable is called a constant. Each product aixiπππ₯π is a term of a polynomial. The highest power of the variable that occurs in the polynomial is called the degree of a polynomial. The leading term is the term with the highest power, and its coefficient is called the leading coefficient.
HOW TO
Given a polynomial expression, identify the degree and leading coefficient.
- Find the highest power ofΒ xΒ to determine the degree.
- Identify the term containing the highest power ofΒ xΒ to find the leading term.
- Identify the coefficient of the leading term.
EXAMPLE 1
Identifying the Degree and Leading Coefficient of a Polynomial
For the following polynomials, identify the degree, the leading term, and the leading coefficient.
- βΒ 3+2×2β4×33+2π₯2β4π₯3
- βΒ 5t5β2t3+7t5π‘5β2π‘3+7π‘
- βΒ 6pβp3β26πβπ3β2
TRY IT #1
Identify the degree, leading term, and leading coefficient of the polynomial 4×2βx6+2xβ6.4π₯2βπ₯6+2π₯β6.
Adding and Subtracting Polynomials
We can add and subtract polynomials by combining like terms, which are terms that contain the same variables raised to the same exponents. For example, 5×25π₯2 and β2×2β2π₯2 are like terms, and can be added to get 3×2,3π₯2, but 3×3π₯ and 3×23π₯2 are not like terms, and therefore cannot be added.
HOW TO
Given multiple polynomials, add or subtract them to simplify the expressions.
- Combine like terms.
- Simplify and write in standard form.
EXAMPLE 2
Adding Polynomials
Find the sum.
(12×2+9xβ21)+(4×3+8×2β5x+20)(12π₯2+9π₯β21)+(4π₯3+8π₯2β5π₯+20)
Analysis
We can check our answers to these types of problems using a graphing calculator. To check, graph the problem as given along with the simplified answer. The two graphs should be equivalent. Be sure to use the same window to compare the graphs. Using different windows can make the expressions seem equivalent when they are not.
TRY IT #2
Find the sum.
(2×3+5×2βx+1)+(2×2β3xβ4)(2π₯3+5π₯2βπ₯+1)+(2π₯2β3π₯β4)
EXAMPLE 3
Subtracting Polynomials
Find the difference.
(7×4βx2+6x+1)β(5×3β2×2+3x+2)(7π₯4βπ₯2+6π₯+1)β(5π₯3β2π₯2+3π₯+2)
Analysis
Note that finding the difference between two polynomials is the same as adding the opposite of the second polynomial to the first.
TRY IT #3
Find the difference.
(β7×3β7×2+6xβ2)β(4×3β6×2βx+7)(β7π₯3β7π₯2+6π₯β2)β(4π₯3β6π₯2βπ₯+7)
Multiplying Polynomials
Multiplying polynomials is a bit more challenging than adding and subtracting polynomials. We must use the distributive property to multiply each term in the first polynomial by each term in the second polynomial. We then combine like terms. We can also use a shortcut called the FOIL method when multiplying binomials. Certain special products follow patterns that we can memorize and use instead of multiplying the polynomials by hand each time. We will look at a variety of ways to multiply polynomials.
Multiplying Polynomials Using the Distributive Property
To multiply a number by a polynomial, we use the distributive property. The number must be distributed to each term of the polynomial. We can distribute the 22 in 2(x+7)2(π₯+7) to obtain the equivalent expression 2x+14.2π₯+14. When multiplying polynomials, the distributive property allows us to multiply each term of the first polynomial by each term of the second. We then add the products together and combine like terms to simplify.
HOW TO
Given the multiplication of two polynomials, use the distributive property to simplify the expression.
- Multiply each term of the first polynomial by each term of the second.
- Combine like terms.
- Simplify.
EXAMPLE 4
Multiplying Polynomials Using the Distributive Property
Find the product.
(2x+1)(3×2βx+4)(2π₯+1)(3π₯2βπ₯+4)
Analysis
We can use a table to keep track of our work, as shown inΒ Table 1. Write one polynomial across the top and the other down the side. For each box in the table, multiply the term for that row by the term for that column. Then add all of the terms together, combine like terms, and simplify.
| 3×23π₯2 | βxβπ₯ | +4+4 | |
| 2×2π₯ | 6×36π₯3 | β2×2β2π₯2 | 8×8π₯ |
| +1+1 | 3×23π₯2 | βxβπ₯ | 44 |
TRY IT #4
Find the product.
(3x+2)(x3β4×2+7)(3π₯+2)(π₯3β4π₯2+7)
Using FOIL to Multiply Binomials
A shortcut called FOIL is sometimes used to find the product of two binomials. It is called FOIL because we multiply the first terms, the outer terms, the inner terms, and then the last terms of each binomial.
The FOIL method arises out of the distributive property. We are simply multiplying each term of the first binomial by each term of the second binomial, and then combining like terms.
HOW TO
Given two binomials, use FOIL to simplify the expression.
- Multiply the first terms of each binomial.
- Multiply the outer terms of the binomials.
- Multiply the inner terms of the binomials.
- Multiply the last terms of each binomial.
- Add the products.
- Combine like terms and simplify.
EXAMPLE 5
Using FOIL to Multiply Binomials
Use FOIL to find the product.
(2xβ18)(3x+3)(2π₯-18)(3π₯+3)
TRY IT #5
Use FOIL to find the product.
(x+7)(3xβ5)(π₯+7)(3π₯β5)
Perfect Square Trinomials
Certain binomial products have special forms. When a binomial is squared, the result is called a perfect square trinomial. We can find the square by multiplying the binomial by itself. However, there is a special form that each of these perfect square trinomials takes, and memorizing the form makes squaring binomials much easier and faster. Letβs look at a few perfect square trinomials to familiarize ourselves with the form.
(x+5)2(xβ3)2(4xβ1)2===x2+10x+25×2β6x+916×2β8x+1(π₯+5)2=π₯2+10π₯+25(π₯β3)2=π₯2β6π₯+9(4π₯β1)2=16π₯2β8π₯+1
Notice that the first term of each trinomial is the square of the first term of the binomial and, similarly, the last term of each trinomial is the square of the last term of the binomial. The middle term is double the product of the two terms. Lastly, we see that the first sign of the trinomial is the same as the sign of the binomial.
PERFECT SQUARE TRINOMIALS
When a binomial is squared, the result is the first term squared added to double the product of both terms and the last term squared.
(x+a)2=(x+a)(x+a)=x2+2ax+a2(π₯+π)2=(π₯+π)(π₯+π)=π₯2+2ππ₯+π2
HOW TO
Given a binomial, square it using the formula for perfect square trinomials.
- Square the first term of the binomial.
- Square the last term of the binomial.
- For the middle term of the trinomial, double the product of the two terms.
- Add and simplify.
EXAMPLE 6
Expanding Perfect Squares
ExpandΒ (3xβ8)2.(3π₯β8)2.
TRY IT #6
Expand (4xβ1)2.(4π₯β1)2.
Difference of Squares
Another special product is called the difference of squares, which occurs when we multiply a binomial by another binomial with the same terms but the opposite sign. Letβs see what happens when we multiply (x+1)(xβ1)(π₯+1)(π₯β1) using the FOIL method.
(x+1)(xβ1)==x2βx+xβ1×2β1(π₯+1)(π₯β1)=π₯2βπ₯+π₯β1=π₯2β1
The middle term drops out, resulting in a difference of squares. Just as we did with the perfect squares, letβs look at a few examples.
(x+5)(xβ5)(x+11)(xβ11)(2x+3)(2xβ3)===x2β25×2β1214×2β9(π₯+5)(π₯β5)=π₯2β25(π₯+11)(π₯β11)=π₯2β121(2π₯+3)(2π₯β3)=4π₯2β9
Because the sign changes in the second binomial, the outer and inner terms cancel each other out, and we are left only with the square of the first term minus the square of the last term.
Q&A
Is there a special form for the sum of squares?
No. The difference of squares occurs because the opposite signs of the binomials cause the middle terms to disappear. There are no two binomials that multiply to equal a sum of squares.
DIFFERENCE OF SQUARES
When a binomial is multiplied by a binomial with the same terms separated by the opposite sign, the result is the square of the first term minus the square of the last term.
(a+b)(aβb)=a2βb2(π+π)(πβπ)=π2βπ2
HOW TO
Given a binomial multiplied by a binomial with the same terms but the opposite sign, find the difference of squares.
- Square the first term of the binomials.
- Square the last term of the binomials.
- Subtract the square of the last term from the square of the first term.
EXAMPLE 7
Multiplying Binomials Resulting in a Difference of Squares
MultiplyΒ (9x+4)(9xβ4).(9π₯+4)(9π₯β4).
TRY IT #7
Multiply (2x+7)(2xβ7).(2π₯+7)(2π₯β7).
Performing Operations with Polynomials of Several Variables
We have looked at polynomials containing only one variable. However, a polynomial can contain several variables. All of the same rules apply when working with polynomials containing several variables. Consider an example:
(a+2b)(4aβbβc)a(4aβbβc)+2b(4aβbβc)4a2βabβac+8abβ2b2β2bc4a2+(βab+8ab)βacβ2b2β2bc4a2+7abβacβ2bcβ2b2Use the distributive property.Multiply.Combine like terms.Simplify.(π+2π)(4πβπβπ)π(4πβπβπ)+2π(4πβπβπ)Use the distributive property.4π2βππβππ+8ππβ2π2β2ππMultiply.4π2+(βππ+8ππ)βππβ2π2β2ππCombine like terms.4π2+7ππβππβ2ππβ2π2Simplify.
EXAMPLE 8
Multiplying Polynomials Containing Several Variables
MultiplyΒ (x+4)(3xβ2y+5).(π₯+4)(3π₯β2π¦+5).
TRY IT #8
Multiply (3xβ1)(2x+7yβ9).(3π₯β1)(2π₯+7π¦β9).
MEDIA
Access these online resources for additional instruction and practice with polynomials.
- Adding and Subtracting Polynomials
- Multiplying Polynomials
- Special Products of Polynomials
1.4 Section Exercises
Verbal
1
Evaluate the following statement: The degree of a polynomial in standard form is the exponent of the leading term. Explain why the statement is true or false.
2
Many times, multiplying two binomials with two variables results in a trinomial. This is not the case when there is a difference of two squares. Explain why the product in this case is also a binomial.
3
You can multiply polynomials with any number of terms and any number of variables using four basic steps over and over until you reach the expanded polynomial. What are the four steps?
4
State whether the following statement is true and explain why or why not: A trinomial is always a higher degree than a monomial.
Algebraic
For the following exercises, identify the degree of the polynomial.
5.
7xβ2×2+137π₯β2π₯2+13
6.
14m3+m2β16m+814π3+π2β16π+8
7.
β625a8+16b4β625π8+16π4
8.
200pβ30p2m+40m3200πβ30π2π+40π3
9.
x2+4x+4π₯2+4π₯+4
10.
6y4βy5+3yβ46π¦4βπ¦5+3π¦β4
For the following exercises, find the sum or difference.
11.
(12×2+3x)β(8×2β19)(12π₯2+3π₯)β(8π₯2β19)
12.
(4z3+8z2βz)+(β2z2+z+6)(4π§3+8π§2βπ§)+(β2π§2+π§+6)
13.
(6w2+24w+24)β(3wβ26w+3)(6π€2+24π€+24)β(3π€β26π€+3)
14.
(7a3+6a2β4aβ13)+(β3a3β4a2+6a+17)(7π3+6π2β4πβ13)+(β3π3β4π2+6π+17)
15.
(11b4β6b3+18b2β4b+8)β(3b3+6b2+3b)(11π4β6π3+18π2β4π+8)β(3π3+6π2+3π)
16.
(49p2β25)+(16p4β32p2+16)(49π2β25)+(16π4β32π2+16)
For the following exercises, find the product.
17.
(4x+2)(6xβ4)(4π₯+2)(6π₯β4)
18.
(14c2+4c)(2c2β3c)(14π2+4π)(2π2β3π)
19.
(6b2β6)(4b2β4)(6π2β6)(4π2β4)
20.
(3dβ5)(2d+9)(3πβ5)(2π+9)
21.
(9vβ11)(11vβ9)(9π£β11)(11π£β9)
22.
(4t2+7t)(β3t2+4)(4π‘2+7π‘)(β3π‘2+4)
23.
(8nβ4)(n2+9)(8πβ4)(π2+9)
For the following exercises, expand the binomial.
24.
(4x+5)2(4π₯+5)2
25.
(3yβ7)2(3π¦β7)2
26.
(12β4x)2(12β4π₯)2
27.
(4p+9)2(4π+9)2
28.
(2mβ3)2(2πβ3)2
29.
(3yβ6)2(3π¦β6)2
30.
(9b+1)2(9π+1)2
For the following exercises, multiply the binomials.
31.
(4c+1)(4cβ1)(4π+1)(4πβ1)
32.
(9aβ4)(9a+4)(9πβ4)(9π+4)
33.
(15nβ6)(15n+6)(15πβ6)(15π+6)
34.
(25b+2)(25bβ2)(25π+2)(25πβ2)
35.
(4+4m)(4β4m)(4+4π)(4β4π)
36.
(14p+7)(14pβ7)(14π+7)(14πβ7)
37.
(11qβ10)(11q+10)(11πβ10)(11π+10)
For the following exercises, multiply the polynomials.
38.
(2×2+2x+1)(4xβ1)(2π₯2+2π₯+1)(4π₯β1)
39.
(4t2+tβ7)(4t2β1)(4π‘2+π‘β7)(4π‘2β1)
40.
(xβ1)(x2β2x+1)(π₯β1)(π₯2β2π₯+1)
41.
(yβ2)(y2β4yβ9)(π¦β2)(π¦2β4π¦β9)
42.
(6kβ5)(6k2+5kβ1)(6πβ5)(6π2+5πβ1)
43.
(3p2+2pβ10)(pβ1)(3π2+2πβ10)(πβ1)
44.
(4mβ13)(2m2β7m+9)(4πβ13)(2π2β7π+9)
45.
(a+b)(aβb)(π+π)(πβπ)
46.
(4xβ6y)(6xβ4y)(4π₯β6π¦)(6π₯β4π¦)
47.
(4tβ5u)2(4π‘β5π’)2
48.
(9m+4nβ1)(2m+8)(9π+4πβ1)(2π+8)
49.
(4tβx)(tβx+1)(4π‘βπ₯)(π‘βπ₯+1)
50.
(b2β1)(a2+2ab+b2)(π2β1)(π2+2ππ+π2)
51.
(4rβd)(6r+7d)(4πβπ)(6π+7π)
52.
(x+y)(x2βxy+y2)(π₯+π¦)(π₯2βπ₯π¦+π¦2)
Real-World Applications
53.
A developer wants to purchase a plot of land to build a house. The area of the plot can be described by the following expression: (4x+1)(8xβ3)(4π₯+1)(8π₯β3) where x is measured in meters. Multiply the binomials to find the area of the plot in standard form.
54.
A prospective buyer wants to know how much grain a specific silo can hold. The area of the floor of the silo is (2x+9)2.(2π₯+9)2. The height of the silo is 10x+10,10π₯+10, where x is measured in feet. Expand the square and multiply by the height to find the expression that shows how much grain the silo can hold.
Extensions
For the following exercises, perform the given operations.
55.
(4tβ7)2(2t+1)β(4t2+2t+11)(4π‘β7)2(2π‘+1)β(4π‘2+2π‘+11)
56.
(3b+6)(3bβ6)(9b2β36)(3π+6)(3πβ6)(9π2β36)
57.
(a2+4ac+4c2)(a2β4c2)
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