Arithmetic Solved Problems

Question 1: The sum of the two numbers is 50, and their difference is 30. Find the numbers.

Solution: Let the numbers be x and y. Now, as per the given situation,

x + y = 50……………………(i)

and x – y = 30………………(ii)

We can write, x = 50-y, from eq.(i),

Therefore, putting the value of x in eq(ii), we get,

50 – y – y = 30

50 -2y = 30

2y = 50-30= 20

y = 20/2 = 10

and x = 50 – y = 50-10 =40

Therefore, the two numbers are 40 and 10.

Question 2: Solve 25 + 5 (27 ÷ 3) – 9.

Solution: 25 + 5(27 ÷ 3) – 9

⇒  25 + 5(9) – 9

⇒ 25 + 45 – 9

⇒ 70 – 9 = 61